3x^2-2x-1200=0

Solution for 3x^2-2x-1200=0 equation:

3x^2-2x-1200=0

a = 3; b = -2; c = -1200;
Δ = b2-4ac
Δ = -22-4·3·(-1200)
Δ = 14404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14404}=\sqrt{4*3601}=\sqrt{4}*\sqrt{3601}=2\sqrt{3601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{3601}}{2*3}=\frac{2-2\sqrt{3601}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{3601}}{2*3}=\frac{2+2\sqrt{3601}}{6}
$